Stoichiometry Calculator

This calculator performs mass-to-mass stoichiometry, the core skill of quantitative chemistry: working out how much of one substance reacts or is produced from a given amount of another, using a balanced chemical equation. Stoichiometry rests on a simple chain of reasoning. You convert the mass of the substance you know into moles using its molar mass, apply the mole ratio from the balanced equation to find the moles of the substance you want, then convert those moles back into a mass using its molar mass. Doing this by hand means juggling three steps and several numbers, which is exactly where mistakes creep in. This tool runs the whole chain for you. You enter the mass of the given substance, its molar mass, the coefficients of the given and wanted substances from the balanced equation, and the molar mass of the wanted substance. The calculator returns the mass of the wanted substance, along with the moles of each and the number of particles involved, so you can follow every step. The mole ratio, taken straight from the balancing coefficients, is the heart of it: it is the bridge that lets the amount of one chemical predict the amount of another. The results update as you type, so you can explore how changing the amount or the ratio affects the outcome. Use it for chemistry homework, for planning a reaction, or for checking a laboratory calculation before you weigh anything out. Remember that the equation must be correctly balanced first, since the coefficients you enter come directly from it. The calculations assume the given substance fully reacts and are rounded for display.

43.97
mass of wanted substance (g)
Moles given0.999
Moles wanted0.999
Particles wanted6.02e+23

Converts mass to moles, applies the mole ratio from the balanced equation, then back to mass. The equation must be correctly balanced. Rounded for display.

How it works

The mass of the given substance is divided by its molar mass to get moles. Those moles are multiplied by the ratio of the wanted coefficient to the given coefficient, taken from the balanced equation, to get the moles of the wanted substance. Finally, those moles are multiplied by the wanted molar mass to get its mass.

Worked example

Decomposing calcium carbonate, CaCO3 to CaO plus CO2, start with 100 grams of CaCO3 (molar mass 100.09). That is 100 divided by 100.09, about 0.999 moles. The 1 to 1 ratio gives 0.999 moles of CO2 (molar mass 44.01), which is 0.999 times 44.01, about 43.97 grams of carbon dioxide.

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