Hydraulic cylinders convert fluid pressure into linear mechanical force, and how much force one produces depends entirely on its geometry and the system pressure driving it. This calculator works out both the extension (push) force and the retraction (pull) force a hydraulic cylinder generates. You enter the bore diameter and rod diameter in millimetres, choose a pressure unit (bar, MPa, PSI or kPa), and enter the system pressure. It returns extension and retraction force in newtons, kilonewtons and metric tonnes, plus a summary of the bore area, the annular (rod-side) area, the pressure converted to megapascals, and the rod-to-bore ratio as a percentage. A detailed breakdown shows the working for each stroke, since extension force uses the full bore area while retraction force uses the smaller annular area left once the rod is subtracted, which is why pull force is always lower than push force at the same pressure. Use it to check whether a cylinder can deliver the force your application needs, whether you are sizing a ram for a press, checking an excavator or loader arm, or specifying a cylinder for a trailer hoist. These are theoretical results based on gauge pressure and cylinder geometry only; actual output will be slightly lower in practice due to seal friction, fluid viscosity losses and back-pressure, so apply a safety factor and confirm critical designs with a qualified hydraulic engineer.
The force produced by a hydraulic cylinder follows directly from Pascal's law: pressure applied to a fluid in a confined space is transmitted equally in all directions. The force acting on a piston face equals the system pressure multiplied by the effective piston area.
During the extension stroke, pressure acts on the full piston face (the bore area):
F_extension = P x A_bore
Where A_bore = π x (D/2)² and D is the bore diameter in metres. Pressure P must be in Pascals (1 bar = 100,000 Pa; 1 MPa = 1,000,000 Pa).
During the retraction stroke, the rod occupies part of the piston face on the rod side. Pressure acts only on the annular area between the bore and the rod:
F_retraction = P x A_ann
Where A_ann = π x ((D/2)² − (d/2)²) and d is the rod diameter. Because A_ann < A_bore, the retraction force is always lower than the extension force at the same pressure.
| Unit | To Pascals | Common use |
|---|---|---|
| Bar | x 100,000 | European hydraulics |
| MPa | x 1,000,000 | Engineering standards (ISO) |
| PSI | x 6,894.76 | Imperial / US systems |
| kPa | x 1,000 | Low-pressure pneumatics |
Hydraulic cylinders convert fluid pressure into linear mechanical force. Common applications include excavator and loader arms (200 to 350 bar), agricultural tractor implements (140 to 210 bar), industrial presses (up to 700 bar), vehicle lift hoists (100 to 150 bar), and steering systems. The cylinder bore and pressure rating are selected to provide sufficient force with an appropriate safety factor, typically 1.5 to 3 times the maximum expected load.
The ratio of retraction force to extension force depends entirely on the rod-to-bore area ratio. A larger rod reduces the annular area and lowers pull force. A common rule of thumb is to keep the rod diameter at roughly 50 to 70 percent of the bore for a good balance of push and pull capacity. Very large rods (close to bore diameter) produce very low pull force but are used when rod buckling under compression is the primary design constraint.
Method: Standard hydraulic engineering formula F = P x A, where P is gauge pressure in Pascals and A is effective piston area in square metres. Extension uses full bore area; retraction uses annular area (bore area minus rod area). This is the universally accepted method in ISO 6022 and related hydraulic engineering standards.
This calculator provides theoretical force based on gauge pressure and cylinder geometry. Actual force output will be slightly lower due to friction in seals, fluid viscosity losses, and back-pressure on the return side. For critical applications always apply an appropriate safety factor and consult a qualified hydraulic engineer.