Hydraulic Cylinder Force Calculator

Calculate the push (extension) and pull (retraction) force produced by a hydraulic cylinder. Enter the bore diameter, rod diameter, and system pressure to get force in Newtons, kilonewtons, and metric tonnes.

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Standard formula  Force = Pressure x Area. Standard hydraulic engineering formula.

1. Cylinder Dimensions

mm
mm
bar

2. Results Summary

Bore area -
Annular area (rod side) -
Pressure (MPa) -
Rod : bore ratio -

Cylinder Force Results

Extension Force (push)
-
-
Extension Force
-
metric tonnes
Retraction Force (pull)
-
-
Retraction Force
-
metric tonnes

Extension Stroke (push)

Bore diameter-
Bore area-
System pressure-
Extension force-

Retraction Stroke (pull)

Bore diameter-
Rod diameter-
Annular area-
System pressure-
Retraction force-
Worked example (default values): A cylinder with a 100 mm bore and 70 mm rod at 200 bar (20 MPa).
Extension area = π x (0.050 m)² = 0.007854 m². Extension force = 20,000,000 Pa x 0.007854 m² = 157.08 kN (16.02 t).
Annular area = π x ((0.050)² − (0.035)²) = π x 0.001275 m² = 0.004006 m². Retraction force = 20,000,000 x 0.004006 = 80.11 kN (8.17 t).

How Hydraulic Cylinder Force is Calculated

The force produced by a hydraulic cylinder follows directly from Pascal's law: pressure applied to a fluid in a confined space is transmitted equally in all directions. The force acting on a piston face equals the system pressure multiplied by the effective piston area.

Extension (Push) Force Formula

During the extension stroke, pressure acts on the full piston face (the bore area):

F_extension = P x A_bore

Where A_bore = π x (D/2)² and D is the bore diameter in metres. Pressure P must be in Pascals (1 bar = 100,000 Pa; 1 MPa = 1,000,000 Pa).

Retraction (Pull) Force Formula

During the retraction stroke, the rod occupies part of the piston face on the rod side. Pressure acts only on the annular area between the bore and the rod:

F_retraction = P x A_ann

Where A_ann = π x ((D/2)² − (d/2)²) and d is the rod diameter. Because A_ann < A_bore, the retraction force is always lower than the extension force at the same pressure.

Pressure Unit Conversions Used

UnitTo PascalsCommon use
Barx 100,000European hydraulics
MPax 1,000,000Engineering standards (ISO)
PSIx 6,894.76Imperial / US systems
kPax 1,000Low-pressure pneumatics

Typical Hydraulic Cylinder Applications

Hydraulic cylinders convert fluid pressure into linear mechanical force. Common applications include excavator and loader arms (200 to 350 bar), agricultural tractor implements (140 to 210 bar), industrial presses (up to 700 bar), vehicle lift hoists (100 to 150 bar), and steering systems. The cylinder bore and pressure rating are selected to provide sufficient force with an appropriate safety factor, typically 1.5 to 3 times the maximum expected load.

Rod Diameter and Force Ratio

The ratio of retraction force to extension force depends entirely on the rod-to-bore area ratio. A larger rod reduces the annular area and lowers pull force. A common rule of thumb is to keep the rod diameter at roughly 50 to 70 percent of the bore for a good balance of push and pull capacity. Very large rods (close to bore diameter) produce very low pull force but are used when rod buckling under compression is the primary design constraint.

Related Calculators

Method: Standard hydraulic engineering formula F = P x A, where P is gauge pressure in Pascals and A is effective piston area in square metres. Extension uses full bore area; retraction uses annular area (bore area minus rod area). This is the universally accepted method in ISO 6022 and related hydraulic engineering standards.

This calculator provides theoretical force based on gauge pressure and cylinder geometry. Actual force output will be slightly lower due to friction in seals, fluid viscosity losses, and back-pressure on the return side. For critical applications always apply an appropriate safety factor and consult a qualified hydraulic engineer.

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