This calculator works out how a known total current splits between two resistors wired in parallel, using the current divider rule from Ohm's law and Kirchhoff's current law. It is useful whenever you need to know how much current flows through each branch of a parallel network, such as sizing components for power dissipation, setting bias currents in a transistor circuit, or building a simple current-sensing shunt. You enter the total current flowing into the parallel combination, choosing amps, milliamps or microamps, then the resistance values of R1 and R2 in ohms. The calculator returns the current through R1 (I1) and R2 (I2), the equivalent parallel resistance, and the voltage across the parallel pair, with a breakdown showing power dissipated in each resistor, total power, and the current ratio between the branches so you can confirm I1 and I2 add back up to your original total current. Because each branch current depends on the other resistor's value, the smaller resistor always carries the larger share of current, the opposite of a voltage divider. Adjust the figures to see how changing either resistor reshapes the split and the power each one must handle. The calculator assumes ideal resistors and a current supplied directly to the parallel pair, so treat results for real circuits with added series resistance as indicative engineering figures rather than a full substitute for circuit analysis.
When two resistors are connected in parallel, they share the same voltage across their terminals because both are connected between the same pair of nodes. The total current flowing into the parallel combination splits between the two branches in inverse proportion to their resistance. This means the branch with the lower resistance carries more current, since current through each resistor equals the shared voltage divided by that resistor's own resistance (Ohm's law).
For two resistors R1 and R2 in parallel with total current I flowing into the combination:
| Quantity | Formula |
|---|---|
| Current through R1 | I1 = I × R2 / (R1 + R2) |
| Current through R2 | I2 = I × R1 / (R1 + R2) |
| Equivalent resistance | Req = (R1 × R2) / (R1 + R2) |
| Voltage across the pair | V = I × Req |
Notice that each branch current formula uses the resistance of the OTHER branch in the numerator. This is the opposite of the voltage divider rule, where each resistor's own value appears in the numerator of its own voltage. The two branch currents always add up exactly to the original total current I, which follows directly from Kirchhoff's current law.
With a total current of 1 A flowing into two resistors in parallel, R1 = 100 ohms and R2 = 200 ohms:
Note that R1 is the smaller resistor and carries the larger share of current (0.667 A versus 0.333 A), confirming that current favours the path of least resistance.
Current dividers are used in electronics to split a known current between two parallel paths, such as sharing load current across parallel resistors for power dissipation reasons, setting bias currents in transistor circuits, or building simple analogue current-sensing shunts. Unlike a voltage divider, a current divider is normally driven by a current source or by a circuit that behaves like one at the node in question, rather than a voltage source directly across both resistors.
For more than two resistors in parallel, the general current divider formula for any branch k is Ik = I × Rtotal_parallel / Rk, where Rtotal_parallel is the equivalent resistance of the whole parallel network (including or excluding branch k depending on the derivation used) or, more commonly, is expressed using conductances: Ik = I × Gk / (G1 + G2 + ... + Gn), where Gk = 1 / Rk. This calculator handles the common two-resistor case directly.
Sources: Current divider rule derived from Ohm's law (V = IR) and Kirchhoff's current law, standard results found in any introductory electrical engineering or circuit analysis textbook.
This calculator assumes ideal resistors with no internal source resistance and a total current supplied to the parallel combination. Real circuits with a voltage source and additional series resistance may need the equivalent resistance combined with the rest of the circuit before applying the current divider rule.
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